20m^2-41m+2=0

Solution for 20m^2-41m+2=0 equation:

20m^2-41m+2=0

a = 20; b = -41; c = +2;
Δ = b2-4ac
Δ = -412-4·20·2
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-39}{2*20}=\frac{2}{40}
=1/20
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+39}{2*20}=\frac{80}{40}
=2
$